[6(x-2)=(3x+30)

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Solution for [6(x-2)=(3x+30) equation: 



6(x-2)=(3x+30)

We move all terms to the left:

6(x-2)-((3x+30))=0

We multiply parentheses

6x-((3x+30))-12=0



We calculate terms in parentheses: -((3x+30)), so:

(3x+30)

We get rid of parentheses

3x+30

Back to the equation:

-(3x+30)



We get rid of parentheses

6x-3x-30-12=0

We add all the numbers together, and all the variables

3x-42=0

We move all terms containing x to the left, all other terms to the right

3x=42

x=42/3

x=14

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